C++ float array initialization [duplicate]

Possible Duplicate:
C and C++ : Partial initialization of automatic structure

While reading Code Complete, I came across an C++ array initialization example:

float studentGrades[ MAX_STUDENTS ] = { 0.0 };

I did not know C++ could initialize the entire array, so I've tested it:

#include <iostream>
using namespace std;
int main() { const int MAX_STUDENTS=4; float studentGrades[ MAX_STUDENTS ] = { 0.0 }; for (int i=0; i<MAX_STUDENTS; i++) { cout << i << " " << studentGrades[i] << '\n'; } return 0;
}

The program gave the expected results:

0 0
1 0
2 0
3 0

But changing the initialization value from 0.0 to, say, 9.9:

float studentGrades[ MAX_STUDENTS ] = { 9.9 };

Gave the interesting result:

0 9.9
1 0
2 0
3 0

Does the initialization declaration set only the first element in the array?

2 Answers

You only initialize the first N positions to the values in braces and all others are initialized to 0. In this case, N is the number of arguments you passed to the initialization list, i.e.,

float arr1[10] = { }; // all elements are 0
float arr2[10] = { 0 }; // all elements are 0
float arr3[10] = { 1 }; // first element is 1, all others are 0
float arr4[10] = { 1, 2 }; // first element is 1, second is 2, all others are 0

No, it sets all members/elements that haven't been explicitly set to their default-initialisation value, which is zero for numeric types.